Graph the following equation y+2=3/5(x+3)

Step-by-step explanation:

It is given

2x−3y=5

we can write it as

3y=2x−5

So we get

y=32x−5

Substituting x=4 in the given equation

y=32(4)−5

So we get

Y=38−5

y=33

By division we get

y=1

Substituting x=−2 in the given equation

y=32(−2)−5

So we get

y=3−4−5

y=3−9

By division we get

y=−3

x4       -2

y      1        -3

Now draw a graph using the points (4,1) and (−2,3)

Join the point through a line and find the value of y

(i) Based on the graph

consider x=4 on X-axis

Now the line joining the two points and a point on the Y-axis gives the value of y

Therefore,when x=4 the value of y=1

(ii) Based on the graph,

Consider y=3 on Y-axis

Now the line joining the two points and a point on the X-axis the value of x

Therefore, when y=3 the value of x=7

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

translate k to n and reflect across the line containing jk.