Find five consecutive odd integers if the sum of the first three integers is 7 more than the sum of the last two.

15, 17, 19, 21, 23

Step-by-step explanation:

You can let the middle number = x, then the numbers are

x-4, x-2, x, x+2, x+4

Plugging it back in to what is given,

x-4+x-2+x = 7+x+2+x+4

3x-6 = 2x + 13

x = 19

The numbers are 15, 17, 19, 21, 23

answer: d. $20

step-by-step explanation:

just took the test

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: