QUESTION 1 PLEASE HELP Part A: Mark the focus of the parabola you are going to create at F(6,4). Draw a horizontal line that is 6 units below the focus. This line will be the directrix of your parabola. What is the equation of the line.
Part B: Construct the line that is perpendicular to the directrix and passes through the focus. The line will be the axis of symmetry of the parabola. What are the coordinates of the point of intersection, A, of the axis of symmetry and the directrix of the parabola?
Part C: Explain how you can locate the vertex, V, of the parabola with the given focus and directrix. Write the coordinates of the vertex.
Part D: Which way will the parabola open? Explain.
Part E: how can you find the value of p? is the value of p for your parabola positive or negative? explain.
Part F: what is the value of p for your parabola?
Part G: based on your responses to part C and E above, write the equation of the parabola in vertex form. show your work.
Part H: construct the parabola tool in geogebra.
Part I: once you have constrcuted the parabola, use geogebra to display its equation. in the space below rearrange the equation of the parabola shown in geogebra, and check whether it matches the equation in the vertex form that you wrote in G.
Part J: focus at (5,-3) and directix y = -6 write the equations of these parabolas in vertex form
focus at (10,-4) and directrix y = 6