Can anyone help with this??

  A

Step-by-step explanation:

Consider figure B. It has a uniform horizontal cross section of  2 m, and a height of 7 m. Its area is ...

  A = bh

  A = (2 m)(7 m) = 14 m²

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Figure A decomposes into a rectangle that is 3 m × 5 m and an additional triangle that has a base of 3 m and a height of (7 -5) = 2 m.

The rectangle part of Figure A has an area of ...

  A = bh

  A = (3 m)(5 m) = 15 m²

Already this area is larger than the area of figure B, and we have not even added in the are of the triangle.

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Figure A has the larger area.

Additional comment

The area of the triangle of figure A is ...

  A = 1/2bh = 1/2(3 m)(2 m) = 3 m²

so the total area of Figure A is (15 m² +3 m²) = 18 m².

what are you trying to solve here

step-by-step explanation: