not sure if anyone can see this but can someone give me the answers i am super confussed and my teacher wont help me at all!

Okay so, to solve these problems what you're gonna want to do is substitute the given x and y values into the equation.

For example, number 7.

11(d-c) + 3(c+d), when c=6, d=9

if d=9, you will substitute the d in the problem to 9.

11(9-c) + 3(c+9)

if c=6 you will substitute c for 6.

11(9-6) + 3(6+9)

You can solve now that you have a simpler problem to work with.

11(9-6) + 3(6+9) first...

11(9-6)  11*9=99   11*-6=-66, so, 11(9-6)= 99-66= 33.

3(6+9) 3*6=18 3*9=27 18+27=45

33+45=78

Your answer for number 7 is 78.

Hope this helps, just do the same for the other problems like this one.

step-by-step explanation: