Which is the graph of f(x) = 3x? A. The graph with X-coordinate marks -2, 0, 2 and 4; Y-coordinate marks 0, 6, 12, 18, 24, and 30. It has curve starts from (-2, 0) and goes on increasing till end. It intersects the y-axis at (0, 1), and passes through (3, 27).
B. The graph with X-coordinate marks -2, 0, 2 and 4; Y-coordinate marks 0, 6, 12, 18, 24, and 30. It has curve starts from (0, 0) and goes on increasing till end. It passes through (2, 6) and (3, 24).
C. The graph with X-coordinate marks -2, 0, 2 and 4; Y-coordinate marks 0, 6, 12, 18, 24, and 30. It has curve starts from (-2, 0) and goes on increasing till end. It intersects the y-axis at (0, 2), and passes through (3, 18).
D. The graph with X-coordinate marks -2, 0, 2 and 4; Y-coordinate marks 0, 6, 12, 18, 24, and 30. It has curve starts from (0, 0) and goes on increasing till end. It passes through (2, 6) and (2.25, 12).
Part B
Determine the y-intercept and horizontal asymptote.

y-intercept:

horizontal asymptote: y =

Jada has a monthly budget for her cell phone bill. last month she spent 120% of her budget, and the bill was 60$. what is jada’s monthly budget

What is the quotient? x+5/ 3x²+4x+5 © 3x2 – 11 + x + s 3x – 11 + 60 x + 5 o 3x2 - 11 - 50 x + 5 3x – 11 - - x + 5

Determine if the following statement is true or false. the normal curve is symmetric about its​ mean, mu. choose the best answer below. a. the statement is false. the normal curve is not symmetric about its​ mean, because the mean is the balancing point of the graph of the distribution. the median is the point where​ 50% of the area under the distribution is to the left and​ 50% to the right.​ therefore, the normal curve could only be symmetric about its​ median, not about its mean. b. the statement is true. the normal curve is a symmetric distribution with one​ peak, which means the​ mean, median, and mode are all equal.​ therefore, the normal curve is symmetric about the​ mean, mu. c. the statement is false. the mean is the balancing point for the graph of a​ distribution, and​ therefore, it is impossible for any distribution to be symmetric about the mean. d. the statement is true. the mean is the balancing point for the graph of a​ distribution, and​ therefore, all distributions are symmetric about the mean.