elijah has three neighbors the sum of all the neighbors ages is 80 the second-oldest neighbor is 28 years old the difference between the ages of the oldest neighbor and the youngest neighbor is 30, what is the age of the youngest neighbor ?

Ans:

Step-by-step explanation:

Let the age of oldest neighbour be x

let the age of youngest neighbour be x-30

According to question,

x+28+x-30 = 80

or, 2x +28-30=80

or,2x+28=80+30

or, 2x=110-28

or, 2x=82

or, x=82/2 = 41

Therefore, The age of oldest neighbour is 41 years

& The age of youngest neighbour= x-30 = 41-30 = 11 years!

its not b

step-by-step explanation:

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x