Let f(x)=x^2+6x−16.
Enter the x-intercepts of the quadratic function in the boxes.

x- intercept is the point where graph of given function touches the x-axis,f(x) becomes 0 at the point where graph of given function touches the x-axis. Therefore, we would to solve x^2+6x−16=0 and find its root.

x-intercepts of the given quadratic function are 2 and -8 .

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.