An integer is 5 more than 4 times another. If the product of the two integers is 51, then find the integers.

Step-by-step explanation:

x = 4y + 5

xy = 51

According to question :

➞ (4y + 5)y = 51

➞ 4y² + 5y = 51

➞ 4y² + 5y - 51 = 0

➞ 4y² + 17y - 12y - 51 = 0

➞ y (4y + 17) - 3(4y + 17) = 0

➞ (y - 3)(4y - 17) = 0

➞ y - 3 = 0

➞ y = 3

Hence,

➞ y = 3

➞ x = 4y + 5

➞ x = 4 (3) + 5

➞ x = 12 + 5

➞ x = 17

∴ The required integers are 3 and 17

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: