Find a polynomial function of degree 3 with real coefficients that has the given zeros. - 2, 3, -4

Polynomial functions' standard form is f(x)=ax^n+bx^n-1...+k

However, polynomials can also be written in intercept form

f(x)=(x-x1)(x-x2)(x-x3)...(x-xn) for roots/zeros x1,x2,x3,...,xn

With the three numbers that you have -2, 3, -4 you can write function

f(x)=(x-(-2))(x-3)(x-(-4))

Then you can simplify and distribute

f(x)=(x+2)(x-3)(x+4)

f(x)=(x^2-x-6)(x+4)

f(x)=x^3+3x^2-10x-24

Which would be the answer

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !

the answer is 31.27mph