Evaluate y = 3x, when x = -4.
A
y = -12
y = 1/81
y = -81

y = -12

Step-by-step explanation:

Plug the value of x (-4) into the original equation and solve:

y = 3(-4)

y = -12

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

560

hope this : )