Read the scenario. A car increases its position at a constant velocity for 5 s. Then, it stops for 55. Which option provides a true statement about a distance-time graph created to represent this motion? The slope of the graph would be increasing for 10 s because the slope represents the passing of time. The slope of the graph would be positive and constant for 5 s, Thon, the stone would be O for 5s because the slope represents velocity. The slope of the graph would be negative and constant for 5 s. Then, the slope would be O for 5 s because the slope represents velocity. The slope of the graph would be positive and increasing for 5 s. Then, the slope would be constant for 5 s because the slope represents velocity

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

his first public project he is asked to create a small scale drawing. the garden is a right triangle with base 25m and height 30m. are you trying to solve for the last side/hypotenuse? the irrational form of the answer would be 5\sqrt{61}