Given: In Triangle XYZ, mZY= 50°, and 2X = ZZ Prove: mZZ = 65°
А
=
B
Statement:
Reason:
1.XYZ is a triangle
1. Given
2. m2X+mZY+mZZ = 180° 2. Postulate
3. mZY = 50°
3. Given
4. ZX=ZZ
4. Given
5.mZX = mZZ
5. Congruency
6. mZZ + 50° + mZZ = 180° 6.[ ? ]
7.mZZ+mZZ = 130° 7.
8.2(m ZZ) = 130° 8. Algebra
9.mZZ = 65°
9. Division Property
of Equality
D

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!

b

step-by-step explanation: