Select the correct answer form each drop-down menu. Given: m SAOB = 42°
m EOF
66°
Prove:
m COD = 72
=
Complete the proof.
It is given that m AOB =
42° and m EOP = 66º. By the
*EOP BOC. Therefore,
m BOC = 66°. By the
m XAOC = 108°, and by the
mXAOC + m COD = 180°After application of the
Dm COD
= 72°

Find the distance between c and d on the number line c=3 and d=11

Arrange the steps to solve this system of linear equations in the correct sequence. x + y = -2 2x – 3y = -9 tiles subtract 3x + 3y = -6 (obtained in step 1) from 2x – 3y = -9 (given) to solve for x. substitute the value of x in the first equation (x + y = -2) to get y = 1. the solution for the system of equations is (-3, 1). x = -15 the solution for the system of equations is (-15, 13). add 3x + 3y = -6 (obtained in step 1) to 2x – 3y = -9 (given), and solve for x. x = -3 substitute the value of x in the first equation (x + y = -2) to get y = 13. multiply the first equation by 3: 3(x + y) = 3(-2) 3x + 3y = -6.

Based on the diagram above, a student determined the hypotanuse of the triangle to be 6√3. determine if the students answer is correct. if not correct find the correct length