Johnson’s table is represented by the vertices of rectangle KLMN. After a rotation 270° clockwise about the origin, the vertices of the rectangle are K'(−3,2) , L'(2,3) , M'(4,−2) , and N'(−2,−3). What were the original coordinates of rectangle KLMN ? Explain your reasoning.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

24

step-by-step explanation:

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