A ball is thrown into the air with an initial velocity of 80 ft/sec. The height of the ball after t seconds in the air is given by h(t) = -16t^2 + 80t + 96. How long will it take for the ball land on the ground? 8 seconds
1 second
6 seconds
12 seconds

Math Review Questions Please Help

h(t) = -16t^2 + 96t You want h(t) = 80 feet 80 = -16t^2 + 96t16t^2 - 96t + 80 = 0t2 - 6t + 5 = 0              [Factored out 16] Solve for t by factoring. There are two answers because the ball passes though 80 feet twice, once on the way up and again on the way back down. So, I’ll say 1 second

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yep b and c r the correct got it! : )