A teacher needs to purchase notebooks and pencils for her students. Notebooks come in packages of 6 and pencils in packages of 10. The table shows the cost of the items. What is the least amount of money the teacher can spend and have the same number of notebooks and pencils.

$31.00

Step-by-step explanation:

Given:

We need to find the LCM of 6 and 10:

Multiples of 6:  6, 12, 18, 24, 30

Multiples of 10: 10, 20, 30

Therefore, the LCM = 30

So the least number of notebooks and pencils the teacher can buy to have the same numbers of each is 30.

⇒ 30 ÷ 6 = 5 packages of notebooks

⇒ 30 ÷ 10 = 3 packages of pencils

5 packages of notebooks = 5 × $5.00 = $25.00

3 packages of pencils = 3 × $2.00 = $6.00

Therefore, the least amount of money the teacher can spend to have the same number of notebooks and pencils (30 each) is:

⇒  $25.00 + $6.00 = $31.00

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

.19875994384

step-by-step explanation:

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