We want to find the zeros of this polynomial:
p(x) = (x+2) (2x^2 + 3x-9)

x = - 2, x = - 3, x =

Step-by-step explanation:

to find the zeros equate p(x) to zero , then

(x + 2)(2x² + 3x - 9) = 0 ← factor the quadratic

(x + 2)(x + 3)(2x - 3) = 0

equate each factor to zero and solve for x

x + 2 = 0 ⇒ x = - 2

x + 3 = 0 ⇒ x = - 3

2x - 3 = 0 ⇒ 2x = 3 ⇒ x =

answer: the answer is 40.82

step-by-step explanation: 3.14 x 13(or half of 26) to the power of 2

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