Michael has $1,059.35 in his checking account. He is going to spend $466.43 on a new television, and he will spend the rest on speakers that cost $43.00 each. Which of the following inequalities would determine the maximum number of speakers, x, Michael can buy without spending more money than he has in his account? A.
$466.43 < $43.00x + $1,059.35
B.
$1,059.35 < $43.00x + $1,059.35
C.
$466.43 + $43.00 + x < $1,059.35
D.
$43.00x + $466.43 < $1,059.35

D. $43.00x + $466.43 < $1,059.35

Step-by-step explanation:

He has $1,059.35.

The amount of speakers he buys is x.

Each speaker is $43.00, and he is buying one television, which is $466.43.

All of the speakers he buys and(+) the television must be less than $1,059.35 because that's all he has. It cannot be more, which is why the equation is $43.00x + $466.43 < $1,059.35.

Hope this helps!

D

Step-by-step explanation:

its $43 each and he wants to buy more than one so that means thats x

that marks out C

so 43.00x +466.43 is less than 1,059.35

I really feel like one of them should have less than/greater than or equal to sign but without I think its D

c

step-by-step explanation:

it would be see because your formula is f(x)=6x, so 6 times 1 is 6 and you go on and the best answer is c.