A rectangular parking lot has length that is 3 yards less than twice its width. If the area of the land is 299 square yards, what are the dimensions of the land?The parking lot has a width of square yards.

• Width = 13 yards

• Length = 23 yards

Explanation:

Let the width of the parking lot = w yards.

The length is 3 yards less than twice its width.

The area of the land = 299 square yards.

We then solve the equation above for w.

Factor the resulting quadratic expression.

Solve for w.

Since w cannot be negative, the parking lot has a width of 13 yards.

Finally, find the length of the parking lot.

The length of the parking lot is 23 yards.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)