In a valid probability distribution, each probability must be between 0 and 1,inclusive, and the probabilities must add up to 1. If a probability distribution5has probabilities1,112, and x, what is the value of X?

Given:

The probability distribution is given by,

To find:

The value of x.

Explanation:

We know that,

The probabilities must add up to 1.

So, we write

Solving for x we get

Therefore, the value of x is,

Final Option D

The value of x is,

dude   i don't even know. i've been trying for hours.

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.