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Mathematics, 30.06.2019 13:40 billyeyelash
Solve. (–k) + k = a. k b. 2k c. –2k d. 0 and solve. 15 + (–15) = a. 15 b. 30 c. –15 d. 0
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(01.03 mc) which of the following is a step in simplifying the expression x multiplied by y to the power of 2 over x to the power of negative 3 multiplied by y to the power of 3, the whole to the power of negative 4. select one: a. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 7 multiplied by y to the power of negative 1. b. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of 12 multiplied by y to the power of negative 12. c. x to the power of negative 4 multiplied by y to the power of negative 8, the whole over x to the power of negative 3 multiplied by y to the power of 3. d. x to the power of negative 4 multiplied by y to the power of negative 2, the whole over x to the power of negative 3 multiplied by y to the power of 3.
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Solve. (–k) + k = a. k b. 2k c. –2k d. 0 and solve. 15 + (–15) = a. 15 b. 30 c. –15 d. 0...
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