Find the slope-intercept form of a line that goes through the point (-1,3) and is parallel to -x+3y=12

First, I would simplify the given equation to find the slope of the parallel line as it will be the same for the line we are looking for.
3y=x+12
y=(x/3)+4

Slope= 1/3

Our equation now looks close, but we need the intercept.
y=(x/3)+B

Plug in the given point to find the intercept.
3=(-1/3)+B
4/3=B

Plug all the known values into the equation to complete the slope-intercept form.
y=(x/3)+4/3

For a 0.25 pfor b o.3pp (0.25+0.3)=0.28