Two friends, bob and ben, each buy one lottery ticket. each ticket contains six numbers from a total of one hundred numbers (0–99). bob chooses the numbers 1, 2, 3, 4, 5, 6, and ben chooses the numbers 39, 45, 66, 72, 74, 89. who has a higher probability of winning

Both have a equal chance of winning.

Both Bob and Ben choose equal numbers i.e. 6. from a set of 100 numbers.

Bob chooses the numbers 1, 2, 3, 4, 5, 6.

This means that the probability that Bob wins is:

     P(Bob wins)=6/100

Also, Ben chooses the numbers 39, 45, 66, 72, 74, 89.

This means that the probability that Ben wins is:

     P(Ben wins)=6/100

Hence, we get that both have the equal probability of winning the game.

cosine

step-by-step explanation: