Mathematics, 01.07.2019 04:50 williampagan9532
Use cramer's rule to solve the following system: –2x – 6y = –26 5x + 2y = 13
Answers: 1
![\left[\begin{array}{ccc}a_1&b_1\\a_2&b_2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}c_1\\c_2\end{array}\right]](/tpl/images/0037/4513/89ff6.png)
![\left[\begin{array}{ccc}-2&-6\\5&2\end{array}\right] \left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}-26\\13\end{array}\right]](/tpl/images/0037/4513/4c54c.png)
![x= \frac{ \left[\begin{array}{ccc}c_1&b_1\\c_2&b_2\end{array}\right] }{ \left[\begin{array}{ccc}a_1&a_2\\b_1&b_2\end{array}\right] } = \frac{c_1b_2-b_1c_2}{a_1b_2-a_2b_1}](/tpl/images/0037/4513/c3be8.png)
![x= \frac{ \left[\begin{array}{ccc}-26&-6\\13&2\end{array}\right] }{ \left[\begin{array}{ccc}-2&-6\\5&2\end{array}\right] } = \frac{(-26)(2)-(-6)(13)}{-2)(2)-(-6)(5)} = \frac{26}{26}=1](/tpl/images/0037/4513/cbd05.png)
![y= \frac{ \left[\begin{array}{ccc}a_1&c_1\\a_2&c_2\end{array}\right] }{ \left[\begin{array}{ccc}a_1&b_1\\a_2&b_2\end{array}\right] } = \frac{a_1c_2-a_2c_1}{a_1b_2-a_2b_1}](/tpl/images/0037/4513/823a4.png)
![y= \frac{ \left[\begin{array}{ccc}-2&-26\\5&13\end{array}\right] }{ \left[\begin{array}{ccc}-2&-6\\5&2\end{array}\right] }= \frac{(-2)(13)-(5)(-26)}{(-2)(2)-(-6)(5)}= \frac{104}{26}=4](/tpl/images/0037/4513/e4462.png)
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Use cramer's rule to solve the following system: –2x – 6y = –26 5x + 2y = 13...
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