In un triangolo rettangolo l'altezza relativa all'ipotenusa divide l'ipotenusa stessa in due segmenti lunghi rispettivamente 39,6 cm e 70,4.calcola perimetro e area del triangolo

Ineed with number 17 i don’t get it at alll

Atriangular field has sides of lengths 21, 39, and 41 yd. find the largest angle. (round your answer to the nearest degree.)

Given: jk ||lm prove: _2 = 27 statement justification 1. jk ||lm 1. given 2.26 = 27 3.22 = 26 2. 3. 4. _2 = 27 4. corresponding angles theorem transitive property of equality vertical angles theorem substitution property of equality