Abuilding lot in a city is shaped as a 30° -60° -90° triangle. the side opposite the 30° angle measures 41 feet. a. find the length of the side of the lot opposite the 60° angle. b. find the length of the hypotenuse of the triangular lot. c. find the sine, cosine, and tangent of the 30° angle in the lot. write your answers as decimals rounded to four decimal places

A) Using the special right triangle ratio for 30-60-90 triangles (which is 1-√3-2, opposite sides of the angles respectively, we can find that the side opposite the sixty degree angle is 41√3.

b) The hypotenuse is the same. Using the ratios, we see that the hypotenuse is 82.

c)sin(30)= opp/hyp = 41/82 = 1/2
cos(30)= adj/hyp = 41√3/82 = √3/2
tan(30)= opp/adj = 41/41√3 = 1/√3 = √3/3

40%=2/550=1/230=3/1056=14/25