Could someone guide me through this one plz a system of two equations is shown below: equation c: a = 4b + 5 equation d: a = 6b − 2 what value of a can be substituted into equation d to solve the system of equations? 4b + 5 6b − 2 4b 6b

the answer is 4b +5

Step-by-step explanation:

a = 4b +5  > first equation

a = 6b - 2  > second equation

Given the first equation a= 4b +5

Here 'a' is alone

In substitution method we substitute the first equation in second equation

So we substitute a= 4b+5 in the place of 'a' in second equation

The value 4b+5 can be substituted in the second equation to solve the system of equations

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.

cosine

step-by-step explanation: