Mathematics, 19.09.2019 04:50 heartprague

If y =12 when x= 6, find x when y=-24

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We have no way of knowing how 'x' and 'y' are related, or whether
changing one of them causes the other one to change at all.
There's no way to know that until you give us at least two points.

For example, let's say that 'x' and 'y' are the coordinates of points on a line.

-- If the equation of the line is [ x = 6 ], then it doesn't matter what 'y' is.
'x' is going to be 6 when y=12, also when y=-24, and also when y=4 million.

-- If the equation of the line is [ y = 2x ], then x=6 when y=12,
and x=-12 when y=-24.

-- If the equation of the line is [ y = 10x - 48 ], then x=6 when y=12,
and x=2.4 when y=-24.

You've told us only that the point (6, 12) is on the line. There are an
infinite number of lines that can go through that point on the graph, and
every one of them has a different value for 'x' when y=-24 .

Answer from: Quest

(1/x + 1)^2 + 6 (1/x + 1) +5

Answer from: Quest

la parábola es el lugar

geométrico en el cual los puntos tienen una distancia idéntica, equidistantes,

de un punto denominado foco, f, y una recta denominada directriz

el radio vector de una

parábola es el segmento que existe entre un punto cualquiera y el foco.

por la ecuación se observa

que la parábola abre hacia la derecha, por lo cual podemos usar las siguientes fórmulas

la ecuación ordinaria de la

parábola es y^2 = 4px, donde p es la longitud desde el vértice de la parábola al

foco.

la fórmula de la directriz

es x + p = 0

resolviendo:

y^2-9x = 0

y^2 = 9x

4p = 9, entonces p = 9/4

entonces el foco tendrá la

coordenada f(9/4,0)

la directriz vendrá

expresada por

x + p = 0

x = -p

x = -9/4

el problema indica que la

ordenada es igual a 6, entonces

(6)^2=9x

x = 36/9

x = 4

entonces el punto al cual

hay que obtener la distancia será p(4,6)

calculando se tendrá: pf =

pf = 6,25 u

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step-by-step explanation:

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If y =12 when x= 6, find x when y=-24...