Mathematics, 15.09.2020 01:01 zairamori14

PLEASE HELP! How do I solve this problem?

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The toughest part of this problem could be deciding what names to give the quantities of one-Euro and two-Euro coins.

-- I called the number of one-Euro coins ' N '.
Each of them is worth 1 Euro, so all ' N ' of them are worth ' N ' Euros.

-- I called the number of two-Euro coins ' T '.
Each of them is worth 2 Euros, so all ' T ' of them are worth ' 2T ' Euros.

-- The total number of coins in Penny's pocket is (N + T), and it says there are 11.

-- Their total value is (N + 2T), and it says the total value is 18.

So now you have two equations, with two unknowns.

   N + 2T = 18
   N + T = 11

Subtract the bottom equation from the top one, and you get:

(N - N) + (2T - T) = (18 - 11)

   T = 7    (there are 7 two-Euro coins in her pocket)

That right there is the answer to the question, so you don't need to go
any farther. But if you wanted to, you could also figure out how many
one-Euro coins there are in her pocket.

Answer from: Quest

{3 + i, 3 - i, 3, -1}

step-by-step explanation:

Answer from: Quest

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

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