Point c ∈ ab , ab = 18 cm. the distance from c to a is 3 cm shorter than the distance to b. find ac and cb.

The measure of AC and CB are 7.5 and 10.5 respectively

The distance between two points on a graph is known as a line.

If C is on a point AB, then;

AC +CB = AB 1

If the distance from C to A is 3 cm shorter than the distance to B, then:

AC = CB - 3 2

Substitute equation 2 into 1 to have;

AC +CB = AB

CB - 3 +CB = AB

2CB - 3 = 18

2CB = 18 + 3

2CB = 21

CB = 21/2

CB = 10.5

Recall that AC = CB - 3

AC = 10.5 - 3

AC = 7.5

Hence the measure of AC and CB are 7.5 and 10.5 respectively

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AC = 7.5 cm

CB=10.5 Cm

Step-by-step explanation:

Given that point  C in between point A and B

AB= 18 cm

lets distance between CA = x

then  distance between CB will be =x +3

Also give that AB =18 cm

So by adding CA and AB

x + x +3 =18

2 x =15

So x=7.5 cm

So

AC = 7.5 cm

CB=10.5 Cm

eve and marks ratios are equivalent

step-by-step explanation: