The weight of jacob’s backpack is made up of the weight of the contents of the backpack as well as the weight of the backpack itself. seventy percent of the total weight is textbooks. his notebooks weigh a total of 4 pounds, and the backpack itself weighs 2 pounds. if the backpack contains only textbooks and notebooks, which equation can be used to determine t, the weight of the textbooks? a: 0.7(t) = t – 4 – 2 b: 0.7(t) = t + 4 + 2 c: 0.7t(4 + 2) = t d: 0.7(t + 4 + 2) = t

d: 0.7(t + 4 + 2) = t .

step-by-step explanation:

c

step-by-step explanation:

it isn't d, because the interquartile range is from 27-57. and the interquartile range is basically half the data, it's pretty obvious.

it isn't b, because like i said earlier, the interquartile range is from 27-57. 57-27 is 30. the real range has to be longer

not a either. although it looks like it, 3/4 of the data is not greater than 27. but if c is wrong than this should be correct

the correct answer is c, because 13 is the point in which the plot starts