![216x^{12}-64=8(27x^{12} - 8) = 8[(3x^{4})^{3} - 2^{3}] = \\ \\ =8(3x^{4}-2)(9x^{8} +6x^{4} +4) = 2(3x^{4}-2)*4(9x^{8}+6x^{4}+4)= \\ \\ (6x^{4}-4)(36x^{8}+24x^{4}+16)](/tpl/images/0191/9583/af121.png)
What is the factorization of 216x^12 – 64?
a. (6x^3 – 4)(36x^6 + 24x^3 + 16)
b. (6x^3 –...
Mathematics, 23.08.2019 21:30 tyrique86
What is the factorization of 216x^12 – 64?
a. (6x^3 – 4)(36x^6 + 24x^3 + 16)
b. (6x^3 – 4)(36x^9 + 24x^3 + 16)
c. (6x^4 – 4)(36x^8 + 24x^4 + 16)
d. (6x^4 – 4)(36x^12 + 24x^4 + 16)
Answers: 1
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