Two bags had 100 kilograms of sugar each. after taking out 3 times as much sugar from bag one than bag two, bag one had half as much sugar left as bag two. how much sugar is left in each bag?

According to the given statement, we can get the equation:

50 - 3x = 1/2 (50-x)

where x = amount removed from bag two, 3x removed from bag one

Then we multiply both sides by 2 (to eliminate the ½)

100-6x= 50-x

Add 6x to both sides

100= 50-5x

Then subtract 50 from both sides

50=5x

Lastly, divide by 5

10=x

Therefore 10 kg of sugar was removed from bag 2

further, 3x= 30, so 30 kg of sugar was removed from bag 1.

50-30=20 kg remaining in bag 1.

50-10=40 kg remaining in bag 2.

this is false ^.^ lol

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form