Solve for n: 21k – 3n + 9p > 3p + 12.

a. n > 2p + 7k - 4

b. n < 2p + 7k - 4

c. n > -4p - 7k + 4

d. n < -4p - 7k + 4

solve for n.21k−3n+9p>3p+12Add -21k to both sides.21k−3n+9p+−21k>3p+12+−21k−3n+9p>−21k+3p+12Add -9p to both sides.−3n+9p+−9p>−21k+3p+12+−9p−3n>−21k−6p+12Divide both sides by -3.−3n/−3    >  −21k−6p+12/−3n < 7k+2p−4

ANSWER IS B

51-50

step-by-step explanation:

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950