Henry rolls 2 number cubes numbered 1 through 6 while playing his favorite board game. he will get a second turn if he rolls a sum that is an even number less than 10. what are henry's chances of getting a second turn when he rolls the number cubes? 7/18 11/18 5/36 17/36 i got 5/18. i added up the amount of different ways to get 2-8. i found 10. either the test is wrong or i'm really bad at counting, and i'm not confident enough to count either of them out.

First of all, we know that each cube can land in 6 different ways,
so two cubes can land in (6x 6) = 36 different ways.

Now let's check your count.  How many ways can you roll a 2, 4, 6, or 8 ?

Cube-A  Cube-B
      1            1              2
      1            3              4
      3            1              4
      2            2              4
      1            5              6
      5            1              6
      2            4              6
      4            2              6
      3            3              6
      2            6              8
      6            2              8
      3            5              8
      5            3              8
      4            4              8

I get 14 ways.

So the probability of success is

         (number of successful ways) / (total possible ways) =

                       (14)                            /            (36)                  =  7/18 .

Just a question- could you organize the data better? i just cannot tell which number are for which bakery. i will be happy to answer this question if you could do this for me! : )