Surface area of a right cone. solve for p s=2b+ph

S = 2b + ph

Lets subtract both sides by 2b

s - 2b = ph

Now, divide both sides by h

(s-2b)/h = p

Hope this helps!

Answer to your question: a. the fundamental theorem of algebra tells you that the equation will have two complex roots since the degree of the polynomial is 2. the roots are ​ x=1±i7√2 .number of roots=degree of polynomialhere, degree of polynomial is 2 so number of roots will be 2.hope it *_*