You are designing a container in the shape of a cylinder. the radius is 6 inches. you want the container to hold at least  324(pi) cubic inches. what is the least possible height of the container?

9 inches

The volume of a cylinder is given by ...

... V = πr²h

The least height will be the height that makes the volume exactly that which is necessary.

... 324π in³ = π·(6 in)²·h . . . . . . fill in the given information

... (324π in³)/(36π in²) = h = 9 in . . . . . divide by the coefficient of h

The least possible container height is 9 inches.

ghjmutmum

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°