Which gives the first two steps to evaluate 6 -2(3 + 5)^2 - 4 ? i need this asap a. add 3 plus 5, square 8 b. subtract 2 from 6, add 3 plus 5 c. square 3, square 5 d. add 3 plus 5, multiply 8 by 2

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

do your own work and don"t cheat.

step-by-step explanation:

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step-by-step explanation: