The smallest package weighed only 1/3 more than 1/2 the weight of the heaviest package. if the two packages combined weighed 100 kilograms, how much did the smaller package weigh?

Let the weight of the heaviet package = X
Weight of the smallest package = X/2+(1/3*X/2)
                                                     = X/2+X/6
                                                     = 2X/3
Then
X+2X/3 = 100
(3X+2X)/3 = 100
5X/3 = 100
X = 300/5
   = 60
Then the weight of the smallest package = 2X/3
                                                                   = 2*60/3
                                                                   = 40
So the weight of the smallest package is 40 Kg.

The correct answer is: b