Acompany manufactured a 16-oz box of cereal. boxes are randomly weighted to ensure the correct amount. if the discrepancy in weight is more than 0.15 oz, the production is stopped. what is the range of acceptable values for production to continue?

The acceptable range will be : 15.85 oz to 16.15 oz

Step-by-step explanation:

Let the weight of the box be = x

As given,

If the discrepancy in weight is more than 0.15 oz, the production is stopped.

And if the discrepancy in weight is less than 0.15 oz then the production will continue.

We can express this as : If ; the production continues

or we can say

Now, z = x-16, and a=0.15, then the value becomes,

Solving for x:

We get the final range as :

Therefore, the answer is :

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explanation

the graph has a slope of 1/3 because each time you move up 1, you go to the right 3. so, slope = rise/run = 1/3. we can cross choice a off the list since we want a slope of 3, rather than 1/3.

the first table shown has a slope of -3. this is because the rise is -6 and the run is 2, so slope = rise/run = -6/2 = -3. note how x increases by 2 each time (run) and y drops by 6 each time (rise). choice b can be eliminated.

the second table has a slope of 3. each time x goes up by 1, the y values increase by 3. slope = rise/run = 3/1 = 3. alternatively you can use the slope formula to prove that the slope is 3 here. use any two rows of values to generate the two points. choice c is one of the answers

the third table also has a slope of 3. let's use the slope formula to prove as such. i'm going to use the first two rows of the table. so i'll use the two points (2,1) and (5,10)

m = slope

m = (y2-y1)/(x2-x1)

m = (10-1)/(5-2)

m = 9/3

m = 3 so we get a slope of 3

choice d is the other answer