Asecurity alarm requires a four-digit code. the code can use the digits 0–9 and the digits cannot be repeated. which expression can be used to determine the probability of the alarm code beginning with a number greater than 7? a.(2p1)(9p3)/10p4 b.(2c1)(9c3)/10c4 c.(10p1)(9p3)/10p4 d.(10c1)(9c3)/10c4

A is the right answer. The probability of the alarm code beginning with a number greater than 7 =.

Step-by-step explanation:

Given:A security alarm requires a four-digit code. The code can use the digits 0–9 and the digits cannot be repeated.  

there is only 2 numbers which are greater than 7 i.e. 8 and 9. ∴ there is 2 possibility for first place.

For the remaining 3 digits there is 9 possibilities (including 1 which would left after choosing 1 from first place )

No of ways for the alarm code beginning with a number greater than 7=

Total ways of code with 4 digits=

Therefore the probability of the alarm code beginning with a number greater than 7 =.

answer is A

Step-by-step explanation:

edg 2021

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

24

step-by-step explanation:

the graph shows 30% of students walk. 80 students were questioned, so the number that said they walk is

30% × 80 = 0.30 × 80 = 24