In δabc, m∠b = m∠c. the angle bisector of ∠b meets ac at point h and the angle bisector of ∠c meets ab at point k. prove that bh = ck.

First, let's illustrate the problem as shown in the picture attached. Then, let's make a two-column proof:

            Statement                                                       Reason
          m∠B = m∠C                                                       Given
             AB = AC                                        Isosceles Triangle Definition
       AK=KB=AH=HC                                      Angle Bisector Postulate
        ΔBKC = ΔHBC                                        Line BC is common side
             BH = CK   Corresponding parts of congruent triangles are congruent

A5 miles because when you look at the chart count how many times it goes into it i don’t even know wha,t i’m saying anymore mpbut long stor6 short it’s 5 miles