At time t = 0 a car moves into the passing lane to pass a slow-moving truck. the average velocity of the car from t =1tot =1+his v = 3(h+1)2.5 +580h−3 ave 10h estimate the instantaneous velocity of the car at t = 1, where time is in seconds and distance is in feet.

The correct given equation is:

v = [3 (h + 1)^2.5 + 580 h – 3] / 10 h

So to solve for the instantaneous velocity at t = 1, we must set h = 0. However we cannot do that since h is in denominator and a number divided by a denominator is infinite. Therefore we must set h to something almost zero. In this case, h = 0.0000001, so that:

at t = 1

v = [3 (0.0000001 + 1)^2.5 + 580 (0.0000001) – 3] / 10 * 0.0000001

v = 58.75 ft/s

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5

51-50

step-by-step explanation: