Mathematics, 07.07.2019 21:20 TheCampingStone
Igot the first part done but i feel as though i did it wrong because i can't seem to get part 2 or 3 done. create a quadratic polynomial function f(x) and a linear binomial in the form (x − a). f(x) = ax^2 + bx + c a = 1 b = 4 c = 6 (x – a) a = -2 f(x) = x^2 + 4x + 6 (x – 2) part 1. show all work using long division to divide your polynomial by the binomial. x + 4 x-2√(x^2+4x+6) -x^2+2x 6x + 6 - 6x + 12 18 is the remainder of x + 4 18 x + 4 + 18/(x-2) part 2. show all work to evaluate f(a) using the function you created. part 3. use complete sentences to explain how the remainder theorem is used to determine whether your linear binomial is a factor of your polynomial function
Answers: 2
Mathematics, 21.06.2019 15:30
Find the gradient of f(x,y,z)equals=left parenthesis x squared plus y squared plus z squared right parenthesis superscript negative 1 divided by 2 baseline plus ln left parenthesis x right parenthesis x2+y2+z2−1/2+ln(xyz) at the point left parenthesis negative 2 comma 1 comma negative 2 right parenthesis(−2,1,−2).
Answers: 1
Mathematics, 21.06.2019 21:50
Determine the common ratio and find the next three terms of the geometric sequence. 10, 2, 0.4, a. 0.2; -0.4, -2, -10 c. 0.02; 0.08, 0.016, 0.0032 b. 0.02; -0.4, -2, -10 d. 0.2; 0.08, 0.016, 0.0032 select the best answer from the choices provided a b c d
Answers: 1
Mathematics, 22.06.2019 00:00
Which of the following would be a correct step in proving that triangle abc is congruent to triangle cda? a. use a protractor to measure the angles and show that all the corresponding angles are equal in measure. this will allow you to prove congruence by aaa. b. show that segment ab is parallel to segment cd and segment ad is parallel to segment cb. this will allow you to prove congruency by asa. c. show that is segment ab is perpendicular to segment ad. this will allow you to prove congruence by sas. d. none of the above.
Answers: 2
Igot the first part done but i feel as though i did it wrong because i can't seem to get part 2 or 3...
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