You reach into a bag of coins and withdraw two coins without replacement. what is the probability you withdrew a nickel and then a dime if the bag held five pennies, ten nickels, and four dimes?

Step-by-step explanation:

Given : Number of nickels in the bag = 10

Number of dimes in the bag = 4

The total number of coins in the bag =

The probability of drawing nickel :-

Total number coins left = 18

The conditional probability of drawing dime, given that a nickel is already drawn :-

Now, the  probability you withdrew a nickel and then a dime is given by :-

Now, the  probability you withdrew a nickel and then a dime

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet