Write an equation in slope-intercept form for the line that passes through (2,-2) and is perpendicular to x + 5y =6

X + 5y = 6
5y = -x + 6
y = -1/5x + 6/5the slope here is -1/5. A perpendicular line will have a negative reciprocal slope. All that means is flip the original slope and change the sign. So we flip -1/5 and make is -5/1and we change the sign...making it 5/1 or just 5. So our perpendicular line will have a slope of 5.

y = mx + b
slope(m) = 5
(2,-2)...x = 2 and y = -2
sub and find b, the y int
-2 = 5(2) + b
-2 = 10 + b
-2 - 10 = b
-12 = b

so ur perpendicular equation is : y = 5x - 12 <=