Mathematics, 08.07.2019 14:50 tts313
Find the equation to the line that is perpendicular to y=2x-3 and goes through the point (-1,2)
Answers: 1
![\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -\cfrac{1}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=-\cfrac{1}{2}[x-(-1)] \\\\\\ y-2=-\cfrac{1}{2}(x+1)\implies y-2=-\cfrac{1}{2}x-\cfrac{1}{2}\implies y=-\cfrac{1}{2}x-\cfrac{1}{2}+2 \\\\\\ y=-\cfrac{1}{2}x+\cfrac{3}{2}](/tpl/images/0065/9379/a3199.png)
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Find the equation to the line that is perpendicular to y=2x-3 and goes through the point (-1,2)...
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