Suppose △ ith ≅ △ apg which congruency statement is true? a) ih ≅ ag b) th ≅ ag c) it ≅ ag d) th ≅ ap

A) IH ≅ AG

Step-by-step explanation:

A property of congruent triangles is known as CPCTC which says that the congruent parts of the corresponding triangle are congruent.

We are given that Δ ITH ≅ Δ APG , then the every part of Δ ITH must be congruent to the corresponding part of  Δ APG.

i.e. Corresponding sides of Δ ITH and Δ APG  are congruent.

Since Side IH in Δ ITH  is corresponding to side AG in Δ APG  [First and last letter]

Then, IH ≅ AG

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

18.75 gallons

step-by-step explanation: