12 ch 5 warm up: people's weights (java) (1) prompt the user to enter five numbers, being five people's weights. store the numbers in an array of doubles. output the array's numbers on one line, each number followed by one space. (2 pts) ex: enter weight 1: 236.0 enter weight 2: 89.5 enter weight 3: 142.0 enter weight 4:

#include <stdio.h>

int main()
{
double d[5] , total = 0, average = 0, max = 0;
int i = 0;
for(i=0; i<5; i++){
printf("Enter Weight %d: ", (i+1));
scanf("%lf", &d[i]);
}
printf("You entered: ");
for(i=0; i<5; i++){
printf("%lf ", d[i]);
if(max < d[i]){
max = d[i];
}
total = total + d[i];
}
average = total / 5;
printf("\nTotal weight: %lf\n", total);
printf("Average weight: %lf\n", average);
printf("Max weight: %lf\n", max);
  
return 0;
}

idn

step-by-step explanation:

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560